MATH STINGER #19 
by Dr. Joel C. Fowler 
Assistant Professor of Mathematics 

New puzzles are as follows. A person owns a gold chain (not circular) with 7 links. Each link is worth $1. 
They wish to open some of the links in the chain in such a way that they can "make change" for any dollar 
amount from $1 to $7. One way to do this would be to open every other link to completely disconnect the 
chain. This would require opening 3 links. A more efficient way would be to open the second and fifth links. 
This produces segments of lengths 1, 1, 2, 1, and 2 (including the opened links). You can verify that any 
dollar amount from 1 to 7 can be obtained as a combination of these lengths. Several puzzles can be based 
on this setup. The first question is whether two links are the fewest that must be opened on the seven link chain. 
Suppose now that the chain has 20 links. What is the fewest number of links on this longer chain that must be 
opened in order to make change for every dollar amount from 1 to 20? Suppose now that three links are to be 
opened on a chain of some length. What is the longest chain for which it is possible to open three links and make 
change for every dollar amount?

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